推荐回答(3个)
把这12个球分成为三组,每组4个,分别为:A1,A2,A3,A4,B1,B2,B3,B4,C1,C2,C3,C4.
A组B组相称,若
相等,则目标球在C组内
取c1,C2,C3与A1,A2,A3相称,若
相等,则目标球为C4
不等,则可知目标球在C1,C2,C3中,且目标球是轻是重
取C1与C2称,若
相等,目标球为C3
不等,根据第二次称重得到的轻重信息可得出目标球
不等,则目标球在A或B组内
取c1,C2,C3,B4与B1,B2,B3,A4相称,若 \\这步是重点,请注意它们的组合
相等,则可知目标球在a1,a2,a3中,且目标球是轻是重
取a1与a2称,若
相等,目标球为a3
不等,根据第二次称重得到的轻重信息可得出目标球
不等且天平方向不变,则可知目标球在b1,b2,b3中,且目标球是轻是重
取b1与b2称,若
相等,目标球为b3
不等,根据第二次称重得到的轻重信息可得出目标球
不等且天平方向改变,则目标球为b4或a4
取a1与b4称,若
相等,目标球为a4
不等,目标球为b4
注:最后一步应该是判断(b4或a4)而不是(b4或c4)
12个球分为三组,每组4个,A1,A2,A3,A4,B1,B2,B3,B4,C1,C2,C3,C4.
A组B组相称,若
相等,则目标球在C组内
取c1,C2,C3与A1,A2,A3相称,若
相等,则目标球为C4
不等,则可知目标球在C1,C2,C3中,且目标球是轻是重
取C1与C2称,若
相等,目标球为C3
不等,根据第二次称重得到的轻重信息可得出目标球
不等,则目标球在A或B组内
取c1,C2,C3,B4与B1,B2,B3,A4相称,若 \\这步是重点,请注意它们的组合
相等,则可知目标球在a1,a2,a3中,且目标球是轻是重
取a1与a2称,若
相等,目标球为a3
不等,根据第二次称重得到的轻重信息可得出目标球
不等且天平方向不变,则可知目标球在b1,b2,b3中,且目标球是轻是重
取b1与b2称,若
相等,目标球为b3
不等,根据第二次称重得到的轻重信息可得出目标球
不等且天平方向改变,则目标球为b4或c4
取a1与b4称,若
相等,目标球为c4
不等,目标球为b4
12个球分为三组,每组4个,A1,A2,A3,A4,B1,B2,B3,B4,C1,C2,C3,C4.
A组B组相称,若
相等,则目标球在C组内
取c1,C2,C3与A1,A2,A3相称,若
相等,则目标球为C4
不等,则可知目标球在C1,C2,C3中,且目标球是轻是重
取C1与C2称,若
相等,目标球为C3
不等,根据第二次称重得到的轻重信息可得出目标球
不等,则目标球在A或B组内
取c1,C2,C3,B4与B1,B2,B3,A4相称,若 \\这步是重点,请注意它们的组合
相等,则可知目标球在a1,a2,a3中,且目标球是轻是重
取a1与a2称,若
相等,目标球为a3
不等,根据第二次称重得到的轻重信息可得出目标球
不等且天平方向不变,则可知目标球在b1,b2,b3中,且目标球是轻是重
取b1与b2称,若
相等,目标球为b3
不等,根据第二次称重得到的轻重信息可得出目标球
不等且天平方向改变,则目标球为b4或c4
取a1与b4称,若
相等,目标球为c4
不等,目标球为b4
只要2分够了
1楼的厉害哦~
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