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(2a+1)的平方+(1-2a)的平方因式分解

2025-04-07 13:29:49

推荐回答（3个）

回答1：

平方差公式而已
原式=(2a+1+1-2a)(2a+1-1+2a)=8a

回答2：

(2a+1)²+(1-2a)²
设2a+1=a,则
a²+(-a)²
=(2a+1+1-2a)(2a+1-1+2a)
=8a

回答3：

(2a+1)的平方+(1-2a)
=4a^2+4a+1+4a^2-4a+1
=8a^2+2
=2(4a^2+1)

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