只知道时针和分针的夹角度数如何求出准确时刻?

2025-04-05 18:11:56
推荐回答(3个)
回答1:

正3点时,时针和分针的夹角为90°(第1步:肯定正点时。时针和分针的夹角度数)时针每小时(60分钟)转30°,则每分钟转0.5°分针每小时(60分钟)转360°,则每分钟转6°(第2步:计算时针和分针转的度数)(第3步:列分程求解)设x分钟时,时针和分针的夹角度数是24°则:时针转了0.5x°,分针转了6x°①按顺时针方向,分针超过了时针时,则有:6x=90+0.5x+24,可以求出x,即为准确时刻,②按顺时针方向,分针没有超过了时针时,则有:6x=90+0.5x⑵4,可以求出x,即为准确时刻.画图,不难找出角度之间的数量关系

回答2:

每10小格是
360o÷12=30o设24o有N小格N∶10=24o∶30oN=8(小格)时针和分针的夹角度数是24度,时针和分针相距8小格,设从3点开始,时针走了n小格,则分针走了6n/0.5
小格,6n/0.5=30+n-811n=22n=26n=12(分钟)答:时间是3点12分钟

回答3:

设为3点X分,24度=圆周的24/360=1/15,也就是1圈为60格1/15圈相当于4格,3点为15格5*X/60+15=x+/⑷得X=19*12/11=228/11=20又8/11分或X=11*12/11=132/11=12分

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