高中数学题,关于双曲线的(会的朋友告诉我详细过程,答案我有)。

2025-04-06 22:00:12
推荐回答(1个)
回答1:

1.两个向量之积为0说明垂直 模之积为2
设两个模分别为s t
s2+t2=40
st=2
(s-t)2=s2+t2-2st=36
绝对值s-t=6=2a
a=3 c=根号10
其他的自己写吧
2.a+b=9
ab=20(a大于b)
a=5b=4c=根号41
离心率根号41除以根号5
3。(e1的平方+e2的平方)/(e1*e2)的平方
化简之后就变成了 1/e1 ²+1/e2²=?
假设椭圆的 参数为a1b1c1 双曲线的参数为 a2b2c2
c1=c2=c
带入离心率
得原式(a1²+a2²)/c平方
假设两条长度为st
s²+t平方=c²
s+t=2a1
s-t=2a2
代入原式
得到答案 就是 0.5
4。这一题比较容易
先考虑它是直角的时候
离心率就是1+根号2
然后就自己判断一下啊
答案就是 (1+根号2,正无穷)
5。注意要把分母里的化成正的
第一个是双曲线 第二个是
好像题目错了 负的减正的怎么可能是1
我怀疑 搞错了

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