(导数)设函数y=(x^2+1)^3,则y✀=

2025-04-13 17:55:28
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回答1:

解设函数y=(x^2+1)^3,则
y'=3(x^2+1)^2(x^2+1)'
=3(x^2+1)^2(2x)
=6x(x^2+1)^2