不定积分求解,要详细过程

2025-03-23 12:01:29
推荐回答(2个)
回答1:

分母提出x
=1/x^2/sqrt(1-1/x^2)dx
令t=1/x,dt=-1/x^2dx
原式=-dt/sqrt(1-t^2)

回答2:

设 x = secu, 则 I = ∫secutanudu/(secutanu) = ∫du
= u + C = arccos(1/x) + C = -arcsin(1/x) + C1