编程比较两个字符串的大小(不用strcmp函数())

2025-03-16 16:50:54
推荐回答(5个)
回答1:

#include

#define N 80

void cmp(char a[N],char b[N])

{

int i=0;

char *p1=a,*p2=b;

while(*(p1+i)==*(p2+i)&&*(p1+i)!='\0')

{

i++;

}

if(*(p1+i)>*(p2+i))

printf("%s>%s\n",p1,p2);

else if(*(p1+i)<*(p2+i))

printf("%s<%s\n",p1,p2);

else

printf("%s=%s\n",p1,p2);

}

int main()

{

char a[N]={"abcdef"},b[N]={"abcdfg"};

char c[N]={"abcdefg"},d[N]={"abcdefg"};

char e[N]={"abcdefg"},f[N]={"abcdeeg"};

cmp(a,b);

cmp(c,d);

cmp(e,f);

return 0;

}

运行效果:

扩展资料:

while语句若一直满足条件,则会不断的重复下去。但有时,需要停止循环,则可以用下面的三种方式:

一、在while语句中设定条件语句,条件不满足,则循环自动停止。

如:只输出3的倍数的循环;可以设置范围为:0到20。

二、在循环结构中加入流程控制语句,可以使用户退出循环。

1、break流程控制:强制中断该运行区内的语句,跳出该运行区,继续运行区域外的语句。

2、continue流程控制:也是中断循环内的运行操作,并且从头开始运行。

回答2:

'\0'是字符串的结尾, a[i]!='\0'判断 有没有到结尾。 '\0'也是可以与字母比较的,它是anscii是 0

回答3:

strcmp函数是用来比较字符串的,而字符串以'\0'作为结尾标志,故要加上&&a[i]!='\0'。

回答4:

a[i] == b[i]&&a[i]!='\0' 此句的前半部分如果成立才去比较后半部分,此时不存在'\0'和'字母的比较。

回答5:

这句中的]&&a[i]!='\0'是什么有什么作用?
防止两个字符串都是null

要是a[100]比b[100]小,也就是a[100]先到'\0'那怎么比较呢!
'\0'就是0

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