C语言中switch case语句的问题

2025-03-15 01:50:17
推荐回答(1个)
回答1:

#
include

void
main()
{
int
I,
k,
a,
b,
c,
d,
e,
f,g;
printf("请输入利润I:\n");
scanf("%d",
&I);
a
=
I
*
(1.0f/10);
//此处强制为浮点类型,不然a一直是0,看你的意思了
b
=
(I
-
100000)
*
75/1000;
c
=
(I
-
200000)
*
5/100;
d
=
(I
-
400000)
*
3/100;
e
=
(I
-
600000)
*
15/1000;
f
=
(I
-
1000000)
*
1/100;
g
=
(I
-
1)
/
100000;
switch(g)
{
case
0:
printf("奖金总数k=%d\n",
a);
break;
case
1:
printf("奖金总数k=%d\n",
a
+
b);
break;
case
2:
case
3:
printf("奖金总数k=%d\n",
a
+
b
+
c);
break;
case
4:
case
5:
printf("奖金总数k=%d\n",
a
+
b
+
c
+
d);
break;
case
6:
case
7:
case
8:
case
9:
printf("奖金总数k=%d\n",
a
+
b
+
c
+
d
+
e);
break;
default
:
printf("奖金总数k=%d\n",
a
+
b
+
c
+
d
+
e
+
f);
break;
}
望采纳~

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