解下列方程(1)2x-20=6x+7(2)3x+7=32-2x(3)7x+2(3x-3)=20(4)3x-7(x-1)=3-2(x-3)(5)x+23?x

2025-04-15 02:23:33
推荐回答(1个)
回答1:

(1)移项得,2x-6x=7+20,
合并同类项得,-4x=27,
系数化为1得,x=-

27
4


(2)移项得,3x+2x=32-7,
合并同类项得,5x=25,
系数化为1得,x=5;

(3)去括号得,7x+6x-6=20,
移项得,7x-6x=20+6,
合并同类项得,x=26;

(4)去括号得,3x-7x+7=3-2x+6,
移项得,3x-7x+2x=3+6-7,
合并同类项得,-2x=2,
系数化为1得,x=-1;

(5)去分母得,3(x+2)-2(x-1)=12,
去括号得,3x+6-2x+2=12,
移项得,3x-2x=12-6-2,
合并同类项得,x=4;

(6)去分母得,3(x-7)-4(5x+8)=12,
去括号得,3x-21-20x-32=12,
移项得,3x-20x=12+32+21,
合并同类项得,-17x=65,
系数化为1得,x=-
65
17