足量铝离子和少量氢氧根反应:Al3+ + 3OH- ==Al(OH)3足量氢氧根和少量铝离子反应:Al3+ + 4OH- = AlO2- + 2H2O
铝离子与氢氧根离子生成氢氧化铝沉淀Al3++3OH- =Al(OH)3↓
Al3+ + 4OH- = AlO2- + 2H2O
少量氢氧根的话Al3+ + 3OH- ==Al(OH)3↓过量氢氧根的话Al3+ + 4OH- = AlO2- + 2H2O