82问答网 > 一只“220V 100W”的电灯，接入220V的电路中，由于导线过长，灯泡的实际功率为81W，则导线上损失的电压

一只“220V 100W”的电灯，接入220V的电路中，由于导线过长，灯泡的实际功率为81W，则导线上损失的电压

2025-03-15 20:18:19
推荐回答（1个）
回答1：

∵P=
U2
R
，
∴灯泡电阻：
R=
U
P额
=
(220V)2
100W
=484Ω；
灯泡的实际电压U实=
P实际R
=
 81W×484Ω
=198V；
导线上消耗的电压U消耗=U-U实=220V-198V=22V．
电路实际电流I=
U实
R
=
198V
484Ω
≈0.4A，
损失的功率P损=IU损=0.4A×22V=8.8W．
故答案为：22；8.8．

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