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电工电子三极管判断工作状态的一道选择题

2025-04-03 10:44:08

推荐回答（1个）

回答1：

发射极箭头向里的是【PNP】三极管，当u1=3v时，u1对-5v应该共等于8v。那么10k与40k电阻比值使基极对地电压约在8v的1/5左右。即基极对地（发射极）正电压约1.6伏。PNP晶体管基极加正极性电压肯定是【截止】状态了，（因为发射极箭头表示电流方向，基极加了正极性就和箭头相抵触了，发射极电流不能进入基极，即截止状态）

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