1）Vb=VccxRb1/(Rb1+Rb2)=6V
Ve=Ve-0.7=5.3V
Ie=Ve/Re=5.3/1=5.3mA≈Ic
Ib=Iv/Ib=0.053mA
Uce=Vcc-Ve=6.7V
2）Ri=Rb1//Rb2//[rbe+(1+β)Re//RL]
=15K//[1K+101x0.5K]=11.6K
Ro=Re//[rbe/(1+β)]=1K//0.0099K≈9.9Ω
3）Au=(1+β)Re//RL]/[rbe+(1+β)Re//RL]
=50.5K/51.5K=0.98
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