化学 杂化轨道问题

用杂化轨道理论说明硫化氢分子的空间构型
2025-04-05 21:44:32
推荐回答(3个)
回答1:

1.杂化轨道是解释为什麽键能都相等而引用的理论,基本上题目上有要求,因为现在有几种理论都可以解释成键的原因!判断的时候看是否成同一种键,或者形成共价键的原子是否相同!sp,sp2,sp3都有可能成等性和不等性!例如:cHcl3是不等性杂化,cH4就是等性杂化,但他们都是sp3杂化!
2.不需要,用价键理论直接解释即可!
3.看它是什麽杂化类型!然后对照相应的构型.例如:sp3杂化,它的空间构型就是四面体!
4.s原子价电子数是6,f成键的单电子是1.所以6+1*4=10
5.邻苯二酚中的两个羟基中氧原子的电负性大,使氢原子裸露,被被另一个氧原子吸引,形成氢键!下一个同理,氧原子变成氮原子.
6.分子键能形成氢键的原子相距较近可以形成分子内,相距较远只能形成分子间,因为氢键具有方向性.
7.熔沸点是针对全部分子而言的,分子与分子之间结合牢固,对外表现的性质稳定,但分子内成键意味著分子间作用力弱,整体对外就不稳定!相似相溶~
邻苯二酚易容于乙醇,不溶於水!

回答2:

硫原子是sp3杂化,除去两个孤电子对,所以空间构型是V型。

回答3:

结合价层电子对互斥理论去学会比较轻松。SO2的中心原子是S,而S分别与两个O形成1个西格玛键和1个派键,S剩下的孤对电子有一对,而成键电子对有2对(不考虑派键),所以,总共有3对电子,因此是SP2杂化。

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