x⼀x-2+x-9⼀x-7=x+1⼀x-1+x-8⼀x-6,在线等!!!!!!

2024-12-05 05:03:43
推荐回答(1个)
回答1:

x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)
x/(x-2)-(x-8)/(x-6)=(x+1)/(x-1)-(x-9)/(x-7)
(x^2-6x-x^2+10x-16)/(x^2-8x+12)=(x^2-6x-7-x^2+10x-9)/(x^2-8x+7)
两式分子不等,分母相等
所以x^2-6x-x^2+10x-16=0
解得x=4