1.已知cos(3π⼀4 +a)=-1⼀3,求cos(π⼀4 -a)2.已知tan(2π⼀3 +a)=√3⼀4,求tan(5π⼀3 -a)

2025-03-25 19:14:20
推荐回答(1个)
回答1:

  1. 解:

    cos(π/4 -a)=cos(-π/4 +a)

                            =-cos(-π/4 +a+π)

                            =-1/3

2.解:tan(5π/3 -a)=-tan(-5π/3+a)

                                =-tan(4π/3+a)=-tan(2π/3+2π/3+a)

                                =-(-√3+√3/4)/(1+√3*√3/4)

                               =3√3/7