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82问答网 > 一道数学不等式：设a、b、c都是整数，求证：bc⼀a+ca⼀b+ab⼀c≥a+b+c

一道数学不等式：设a、b、c都是整数，求证：bc⼀a+ca⼀b+ab⼀c≥a+b+c

2025-03-16 06:19:50

推荐回答（2个）

回答1：

正整数的话
bc/a+ca/b+ab/c
=bc/2a+bc/2a+ca/2b+ca/2b+ab/2c+ab/2c
=(ca/2b+ab/2c)+(bc/2a+ab/2c)+(ca/2b+bc/2a)
≥a+b+c

回答2：

发DE发

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