少量cl2通入足量FeI2溶液中,与足量cl2通入少量FeI2溶液中,他们的离子方程式与化学方程式

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2025-04-07 08:13:59
推荐回答(1个)
回答1:

少量cl2通入足量FeI2溶液中,2I- +Cl2=2Cl- +I2

与足量cl2通入少量FeI2溶液中2Fe2+ +4I- +3Cl2=2Fe3+ +6Cl- +2I2
这个问题,考试一般只考离子方程式

I-有强还原性,Cl2有强氧化性,
I-被Cl2氧化,生成I2
Cl2被I-还原,生成Cl- -------这是不足时的反应

而当Cl2充足时,上步所生成的FeCl2会继续和Cl2反应,即
2FeCl2+Cl2=2FeCl3,即Fe+2 被Cl2继续氧化成Fe+3,

而将FeI2+Cl2=FeCl2+I2 和2FeCl2+Cl2=2FeCl3 两个方程式综合起来就得到方程式2FeI2+3Cl2=2FeCl3+2I2 (足量)了

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