解方程:2x(x-3)-(x-3)(x+6)=x^2+12

2024-12-05 05:05:38
推荐回答(3个)
回答1:

2x(x-3)-(x-3)(x+6)=x^2+12
(x-3)(2x--x-6)=x^2+12
(x-3)(x-6)=x^2+12
x^2-9x+18=x^2+12
-9x+6=0
x=-2/3

回答2:

2x^2-6x-(x^2+3x-18)=x^2+12
2x^2-6x-x^2-3x+18=x^2+12
2x^2-2x^2-6x-3x+18-12=0
-9x+6=0
-9x=-6
x=2/3

回答3:

2/3