设函数f(u)在(0,+∞)内具有二阶导数,且z=f(√(x^2+y^2))满足等式(δ^2 x)

2025-04-13 13:06:46
推荐回答(2个)
回答1:

简单计算一下即可,答案如图所示

回答2:

z = f[√(x^2+y^2)]
∂z/∂x = [x/√(x^2+y^2)]f'
∂^2z/∂x^2 = [y^2/(x^2+y^2)^(3/2)]f' + [x^2/(x^2+y^2)] f''
同理 ∂^2z/∂y^2 = [x^2/(x^2+y^2)^(3/2)]f' + [y^2/(x^2+y^2)] f''
∂^2z/∂x^2 + ∂^2z/∂y^2 = f'/√(x^2+y^2) + f'' = 0
即 f'’(u) + f'/u = 0