解：原式={[(x²+4)/x]-4}÷[(x²-4)/(x²+2x)]={(x²+4)/x-(4x/x)}÷{(x-2)(x+2)/[x(x+2)]}=[(x²+4-4x)/x]÷[(x-2)/x]=[(x-2)²/x]×[x/(x-2)]=x-2=-1-2=-3
