2(x-y)(x+y)-(2x-y)(x+2y)
解:原式=2(x^2-y^2)-(2x^2+3xy-2y^2)
=2x^2-2y^2-2x^2-3xy+2y^2
=-3xy
2(x-y)(x+y)-(2x-y)(x+2y)
解:=2(x^2-y^2)-(2x^2+4xy-xy-2y^2)
=2x^2-2y^2-2x^2-3xy+2y^2
=-3xy
2(x-y)(x+y)-(2x-y)(x+2Y)
=2(x^2-y^2)-(2x^2+4xy-xy-2y^2)
=2x^2-2y^2-2x^2-3xy+2y^2
=-3xy
2x^2-2y^2-2x^2+2y^2-3xy
=-3xy