(x^2+4x+3)(x^2+6x+8)-48 分解因式

(x^2+4x+3)(x^2+6x+8)-48 分解因式X^4+Y^4-3X^2Y^2
2024-11-27 23:44:28
推荐回答(1个)
回答1:

(x^2+4x+3)(x^2+6x+8)-48
=(X+1)(x+3)(x+2)(x+4)-48
=(X+1)(x+4)(x+3)(x+2)-48
=(X^2+5X+4)(x^2+5x+6)-48
=(x^2+5x)^2+10(x^2+5x)+24-48
=(x^2+5x+12)(x^2+5x-2)

X^4+Y^4-3X^2Y^2
=(x^2+y^2)^2-2x^2y^2-3X^2Y^2
=(x^2+y^2+√5xy)(x^2+y^2-√5xy)