c++ 如何让指针指向字符数组

2025-03-14 22:15:29
推荐回答(4个)
回答1:

C++指向字符数组的指针,需要满足字符数组名作为第一个元素地址,指针保存在另一个对象的地址;案例代码如下:

#include 
#include 
#include 
#include 
using namespace std;
int main()
{
 char *sa="Allan";
 cout< //sa保存的是第一个字符的地址,对sa进行解引用得到第一个字符;
 cout<<*sa< char sb[]={'B','o','b'};
 //内存中有大量空字符
 cout< char sc[]={'S','a','m','\0'};
 cout< cout<<*sc< char *sar[]={"Allan","Tom","Peter","Raees","Umer"};
 //将(字符指针的)数组的一对迭代器传递给(字符指针的)列表,将列表初始化为
 //数组中的一段元素的副本
 list slst(sar,sar+5);
 vector svec;
 string str1(sa);
 cout< //在VS2005上没有"预期的运行时错误"(C++ Primer)
 string str2(sb);
 cout< string str3(sc);
 cout< svec.assign(slst.begin(),slst.end());
 for(list::iterator lit=slst.begin();lit!=slst.end();++lit){
  cout<<*lit<<" ";
 }
 cout< for(vector::iterator vit=svec.begin();vit!=svec.end();++vit){
  cout<<*vit<<" ";
 }
 cout< system("pause");
 return 0;
}

回答2:

其实指针也是一级一级的,即指针还可以被指向:
char<-- char*(或一维数组名)<-- char**(或二维数组名)<--char***(或三维数组名) ......
char *StrArray 是字符指针,指向一个字符.
char a[4][20]中的a是二级数组名,存放的是字符指针的指针(二级数组的首地址)
StrArray[i]相当于一个字符.a[i]是一个字符指针(指向二维数组某一行的首地址)---不对等,当然不能赋值.
char **StrArray;
StrArray=new char *[4];
char a[4][20];
int i;
for(i=1;i<=4;i++)
StrArray[i]=a[i];//这样就都是字符指针了.

回答3:

char *StrArray;//字符指针!!
StrArray=new char[4];//把这句也去了,没什么用直接让指针复0!!
char a[4][20];
int i;
for(i=1;i<=4;i++)
StrArray[i]=a[i]; strArray[i]就变成字符了!!

把char *StrArray改成char **StrArray

#include
using namespace std;
int main()
{
char **StrArray=0;
char a[4][20];
int i;
for(i=1;i<=4;i++)
StrArray[i]=a[i];
system("pause");
return 0;
}

回答4:

char *StrArray,new char[4];
StrArray=new char[4];

这样应该没有问题了

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