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82问答网 > 挂在弹簧测力计上的铁块重7.9N，当它全部浸没在水中时，弹簧测力计的示数

挂在弹簧测力计上的铁块重7.9N，当它全部浸没在水中时，弹簧测力计的示数

2025-03-16 16:16:14

推荐回答（1个）

回答1：

（1）铁块全部浸没时，所受浮力：
F_浮=G-F′=7.9N-6.9N=1N；
（2）当铁块一半进入水中时，排开水的体积变为原来的一半，
根据F_浮=ρgV_排可知，受到的浮力减半，即F_浮′=

1

2

F_浮=

1

2

×1N=0.5N．
故答案为：1；0.5．

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