1、产物是 NH4Cl,浓度是从0.05 mol/L,求其 pH 值:2、计算: [H+] = (k·c)1/2 = (10^-9.26 x 10^-1.3 )1/2 = 10^-10.56 /2 = 10^-5.28 pH = 5.28