利用诱导公式求三角函数值 Sin(-31/6×π)

2025-04-02 19:13:01
推荐回答(3个)
回答1:

sin(-31π/6)
=-sin(31π/6) 此步骤应用的是奇函数的性质
=-sin[(30+1)π/6]
=-sin(5π+π/6)
=-sin(π+π/6)
=sin(π/6)
=1/2

回答2:

Sin(-31π/6)
=Sin[-36π+5π)/6]
=sin(-6π+5π/6)
=sin(5π/6)
=sin(π-π/6)
=sin(π/6)
=1/2

回答3:

Sin(-31/6×π)
=
Sin(-31/6×π+ 6π)
=sin(5π/6)
=sin(π/6)

=1/2