一道初二物理计算题

2024-11-22 17:06:10
推荐回答(4个)
回答1:

您好!

应该是50摄氏度

因为:标准大气压下的冰水混合物温度规定是0摄氏度 沸水温度规定是100摄氏度 也就是说4厘米代表的是0摄氏度 24厘米代表的是100摄氏度 温度计上从4厘米到24厘米的距离代表的是100摄氏度 即是这个温度计上1厘米代表5摄氏度 而温度计上的起点0点处代表的是-20摄氏度 上面的14厘米代表14*5=70摄氏度 从0点开始算 要减去20摄氏度(4厘米开始才是0摄氏度) 所以温度为50摄氏度

回答2:

50度,因为4厘米对应0度,24厘米对应100度,而14厘米在4厘米和24厘米中间,所以14厘米对应50度

回答3:

50

回答4:

O
C
|
o--------+
E
A
|
---------+B----
|
|
|
O
D
AB为
角CAE=30度
->
角ACE=60度
角EAD=60度
->
角CAD=90度
->
CD长=2*AC长,
且CB=BD,因此CB=AC
由于
角ACE=60度,CB=AC,因此
三角形CAB
是等边三角形。而AE又是BC
边上的中垂线,EB=20m因此BC=2*EB=40m
40m
额地娘咧,放过我这个答案吧。

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