求-11π⼀4的三角函数值

用定义法求
2024-11-23 02:05:39
推荐回答(2个)
回答1:

-11π/4=4π-11π/4=5π/4=π+π/4,
sin(-11π/4)=sin(π+π/4)=-sinπ/4=-√2/2,
tan(-11π/4)=tan(π+π/4)=tanπ/4=1,
cos(-11π/4)=cos(π+π/4)=-cosπ/4=-√2/2,

回答2:


供参考。